1) Consider a 6-variable Boolean function f(x1, x2, x3, x4, x5, x6)= f1(x1, x2, x3, x4) . f2(x4, x5, x6) where f1(x1, x2, x3, x4) = (1,2,3,5,7,12,14) - x1 is the most significant bit and f2(x4, x5, x6) = (3,4,5,6,7) - x4 is the most significant bit. a) Obtain a minimal sum-of-product (SOP) expression for f1 and f2 with minimum literal counts. b) Obtain a minimal product-of-sum (POS) expression for f with a minimum literal count.

1) Consider a 6-variable Boolean function f(x1, X2, X3, X4, X5, X6)=fi(X1, X2, X3, X4). f2(X4, X5, X6) where fi(x1, X2, X3, X4) =11 (1,2,3,5,7,12,14) - Xi is the most significant bit and f2(x4, X5, X6) II (3,4,5,6,7) - x4 is the most significant bit. a) Obtain a minimal sum-of-product (SOP) expression for fi and f2 with minimum literal counts. b) Obtain a minimal product-of-sum (POS) expression for f with a minimum literal count