Question: 1. Consider the following java code. int x = 5; x++; Give equivalent MIPS ISA. Assume compiler will keep x in $s0 ($16). 2. What
1.
Consider the following java code.
int x = 5;
x++;
Give equivalent MIPS ISA. Assume compiler will keep x in $s0 ($16).
2.
What will be in $8 after executing the following statements?
addi $8, $0, 5
add $8, $8, $8
1. What will be in $8 after execution?
addi $8, $0, 5
sll $8, $8, 2 // shifting $8 left twice (logical shift- assume no sign)
4. What will be in $8 after execution?
Assume $9 contains a valid RAM address.
addi $10, $0, 5
sw $10, 8($9)
addi $9, $9, 8
lw $8, 0($9)
5.
Consider the SPIM code below.
.globl main
.text
main:
ori $t1, $0, 10
ori $t2, $0, 11
add $t3, $t1, $t2
move $t4, $t3
The following image shows a screen shot of QtSPIM page when this program is loaded, and executed in step-by step fashion. Current instruction is highlighted.
What will be the next PC value?
move is not included in MIPS ML. How it is converted?
Register R9 contains a why?
What will be R12 after next 3 instructions are executed?
Consider the following line. What is 012a5820 stands for?
012a5820 add $11, $9, $10
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