Question: 1. Consider x 2 y + ( x 2 +x ) y' + (2 x- 1) y = 0 , (1-1) a)Can you use the
1. Consider
x2 y" + (x2+x) y' +(2x-1) y = 0 ,(1-1)
a)Can you use the Frobenius method to find a general solution?
b)Find the indicial equation based on (38) on page 210 and calculate the roots r1 and r2 , (r1?r2) (Hint, use the l'Hopital's rule, if necessary) ;
c)Use the recursive approach, verify the indicial equation;
d)Based on theorem 4.3.1, can you first use r2 to have the general solution? And explain your judgement.
e)Find the general solution of y1 with r1 and calculate the coefficient up to c4 and also find the general expression of the recursion formula, (recursion formula for y1)
f)Find the general solution of y2 based on theorem 4.3.1. (Hint, set d2 = 0)
theorem 4.3.1 and No.(38) is in the following picture

THEOREM 4.3.1 Regular Singular Point; Frobenius Solution Let :1: = 0 be a regular singular point of the differential equation y\" + p(w)y' + My = 0, (:c > 0) (37) with 3:1)(33) 2 pa + p13: + and w2q(:r:) 2 go + qlm + having radii of convergence R1, R2 respectively. Let r1, m be the roots of the indicial equation 7'2 + (p3 - 1)?' + go 2 0, (33) where an 2 T2 if the roots are real. (Otherwise they are complex conjugates.) Seeking y(:c) in the form y(a:) = 1:" Z ants" :- Z anwn'\
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
