Question: 1 def foo ( seq ) : 2 pos = bar ( seq ) 3 a = seq [ :pos ] 4 b = seq

1 def foo(seq):
2 pos = bar(seq)
3 a = seq[:pos]
4 b = seq[pos+1:]
5 return a+b
6
7 def bar(sub):
8 return sub[0]
9
10 p =[2,0,-1,4]
11 p = foo(p)
12 print(p)
Answer the questions dasuming the entire code has been executed:
Fill in the value(s) for (a):
Fill in the value(s) for (b):
Fill in the value(s) for (c):
Fill in the value(s) for (d):
What is the value of
when line 4 is executed:
What will be printed to the terminal as a result of executing line 12?:
 1 def foo(seq): 2 pos = bar(seq) 3 a = seq[:pos]

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