Question: 1 def isvowel (c): Return True iffis a vowel. If Statements Using Else Parameters: c (str): Character to check if it is a

 1 def isvowel (c): " " "Return True iffis a vowel.

1 def isvowel (c): " " "Return True iffis a vowel. If Statements Using Else Parameters: c (str): Character to check if it is a vowel In the previous question, we used an if statement to run code when a condition was True. Often, we want to do something if the condition is False as well. We can achieve this using else: Returns: bool: True if c' is a vowel, otherwise False 10 return c =: 'a, or c := 'e' or c == '1' or c == 'o' or c == 'u. if condition: 12 13 The above definition uses or, below is an alternative definition that uses 14 15 def is vowel (c): 16 17 18 char - input Please enter a character ' 19 code if true [code if true...1 else: code if falge [code if false...1 return cin 'aeiou Here, if condition evaluates to False, then Python will run the block of code under the elBe statement. For example, this code will print 'Python print( 'Monty') else: print(' Python') Prompt the user to enter a character, and then print either 'vowel' or consonant' as appropriate You may use the is_vowel function we've provided. You can call this with is-vowel (argument) e.g vowel or not = is vowel(a variable). Alternatively you can just perform the logical test in the if condition

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