1/ Find the equation for a quadratic function that has horizontal intercepts at t = -2 and t = 5 and passes through the point (3, -5). answer the the form f(x)=ax^2+bx+c , and enter the values for a, b, and c in the boxes below. a = b = c =

2/ Let f(t)=2^t2t if t0

f(t)= t if t<0

t	-2	-1	0	1	2
g(t)	3	1	-1	0	-2

and h(t)=t1 . Find (fg)(2) .

3/ Let f(t)=2^t2t if t0

f(t)= t if t<0

t	-2	-1	0	1	2
g(t)	3	1	-1	0	-2

and h(t)=t1 . Find (hf)(2) .

4/ Let f(t)=2^t2t if t0

f(t)= t if t<0

t	-2	-1	0	1	2
g(t)	3	1	-1	0	-2

and h(t)=t1 . Find (gh1)(0) .

5/ Find the inverse of the function Q=f(t)=1/4(x1)^3 +2.

Your answer should be able to be written in the form oot(a)(bQ+c)+d or (bQ+c)^(1/a) +d . . What are the values you have for a, b, c, and d?