Question: 1 Find the equation for the plane through Po( -2, - 6,6) perpendicular to the following line. X = - 2-t. y = - 6-

1 Find the equation for the plane through Po( -2, -

1

6,6) perpendicular to the following line. X = - 2-t. y =

Find the equation for the plane through Po( -2, - 6,6) perpendicular to the following line. X = - 2-t. y = - 6- 4t, z =4t, - co - t = 00 Using a coefficient of - 1 for x, the equation of the plane is

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