1.)

Find the equivalent impedance Zeq seen by the source when Vs = 5 cos (2t) v, C = 2 F, R = 3 0 and L = 1 H. (Give angles in degrees and round final answers to two decimal places.) Calculate the voltage across each component - capacitor, resistor and inductor. (Give angles in degrees and round final answers to two decimal places.) C Vs The equivalent impedance seen by the source is + 3.473 Q = 60.255 at an angle of Q. The voltage across the capacitor is at an angle of The voltage across the resistor is at an angle of V. The voltage across the inductor is at an angle of V.Use phasor techniques to determine the current supplied by the source given that V =12 4:00 1M? = 4 Q, C =12 HF. L = 6 rnH and Ln = 2000' radr'sec. sine The impedance seen by the source is Z =|:| /_' |:| 0 . {Round the magnitude to three decimal places and the angle to two decimal places.) The current supplied by the source is | =|:| A\" |:| D A. {Round the magnitude to three decimal places and the angle to two decimal places.) Given 2 complex voltages, V, = 4.3 v = 13 + j8 v: a. Convert V, from polar to rectangular form and V2 from rectangular to polar form (Give answers to 2 decimal places.): V1= V2 = b. Calculate (Give answers to 2 decimal places.): V1 + V2 Give your answer in rectangular form. V1 + V2 = + V2 - V2. Give your answer in rectangular form. V2 - V2 = + V V1 * V2. Give your answer in both polar and rectangular forms. V1 * V2 = + j V2 / V1. Give your answer in polar form. V2 / V1 = V 1 / V1: Give your answer in polar form. 1 / V1 = V