1. Find the errors in the code below, correct and make sure the code runs.

2. When trying to find the acidity of a solution of magnesium hydroxide in hydrochloric acid, the following equation is obtained: 

A(x) = x³ +3.5x² - 40 where x is the hydronium ion concentration. 

3. Find the hydronium ion concentration for a saturated solution using the roots function on OCTAVE. 

4. The roots of the equation using f zero near 2.

5. Find the minimum values for the set of equations; indicate if the solution has on converged. 

                                            x² + 4y² - 1 = 0 

                                            4x⁴ + y² - 1 = 0

Transcribed Image Text:

function secant () f=(x) x^3+x-3; e-le-6; x0=1000; xl=x0-1; [solution, no_iterations] = secant (f, x0, x1); if no iterations> 0 solution is found fprintf('number of function calls: %d\n',2 + no_iterations); fprintf('a solution is: f\n', solution); else end end function [solution, no_iterations] =secant ( x0, xl) f_x0=f(x0); f_xl=f(x1); iteration_counter = 0; while abs (f_xl)>e && iteration_counter<100 try denominator = (f_x1 x = x1-f(xl) /denominator; catch break end fprintf('error-denominator zero for x= \n', xl) x0=x1; x1=x; - end f_x0)/(x1 - x0); f_x0=f_xl; f_xl=f(x1); iteration counter = iteration_counter +1; end solution found or too many iterations if abs (f_xl)>e iteration_counter = -1; function secant () f=(x) x^3+x-3; e-le-6; x0=1000; xl=x0-1; [solution, no_iterations] = secant (f, x0, x1); if no iterations> 0 solution is found fprintf('number of function calls: %d\n',2 + no_iterations); fprintf('a solution is: f\n', solution); else end end function [solution, no_iterations] =secant ( x0, xl) f_x0=f(x0); f_xl=f(x1); iteration_counter = 0; while abs (f_xl)>e && iteration_counter<100 try denominator = (f_x1 x = x1-f(xl) /denominator; catch break end fprintf('error-denominator zero for x= \n', xl) x0=x1; x1=x; - end f_x0)/(x1 - x0); f_x0=f_xl; f_xl=f(x1); iteration counter = iteration_counter +1; end solution found or too many iterations if abs (f_xl)>e iteration_counter = -1;

Answer rating: 100% (QA)

1 The errors in the code are as follows The function secant is missing input arguments f and e The line x01000 x1x01 should be indented inside the secant function The line solution noiterations secant ... View the full answer