Question: 1. Given (ACBD)=-1. The perpendiculars to CD at the points C,D meet a transversal through A in P,Q. Show that AB bisects the angle PBQ.

1. Given (ACBD)=-1. The perpendiculars to CD at the points C,D

1. Given (ACBD)=-1. The perpendiculars to CD at the points C,D meet a transversal through A in P,Q. Show that AB bisects the angle PBQ. 2. Show that AB CD + AC DB + AD BC = 0 given the points are collinear

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