1. Given that the acceleration vector is a(t)=(−4cos(−2t),−4sin(−2t),5t)a(t)=(−4cos⁡(−2t),−4sin⁡(−2t),5t),

the initial velocity is v(0)=(1,0,1)v(0)=(1,0,1),
and the initial position vector is r(0)=(1,1,1)r(0)=(1,1,1), compute:

A. The velocity of vector: 1-2sin(2t))i + 2-2cos(2t)j+ __ k. (Find k)

B.  The position vector r(t): (cos(2t)+t)i + __ j + __ k