1. Given the life table below, and a constant force of interest d = 5%, compute the following. (Note that Z means a present value random variable for a single insurance payout as appropriate to the notation, like in the lectures) a) A5 b) A::41 1 C N c) A5:1' (that is, 4E5) d) 4|A5 e) Var(25) f) Var(252) li 0 100,000 1 97,000 2 94,000 3 89,000 4 82,000 5 74,000 6 65,000 7 55,000 8 43,000 9 34,000 10 22,000 10,000 12 0 LOCO 11 1. Given the life table below, and a constant force of interest d = 5%, compute the following. (Note that Z means a present value random variable for a single insurance payout as appropriate to the notation, like in the lectures) a) A5 b) A::41 1 C N c) A5:1' (that is, 4E5) d) 4|A5 e) Var(25) f) Var(252) li 0 100,000 1 97,000 2 94,000 3 89,000 4 82,000 5 74,000 6 65,000 7 55,000 8 43,000 9 34,000 10 22,000 10,000 12 0 LOCO 11