1. Identify the recursive structure of the input (in this case, always a nested list), and write down the code template for nested lists:

def f(obj: Union[int, list]) -> ...:
if isinstance(obj, int):
...
else:
...
for sublist in obj:
... f(sublist) ...
...

2. Implement the base case(s) directly (in this case, a single integer).
3. Write down a concrete example with a somewhat complex argument, (in this case, a nested list with around 3 sub-nested lists), and then write down the relevant recursive calls and what they should return.
4. Determine how to combine the recursive calls to compute the correct output. Make sure you can express this in English first, and then implement your idea.

HINT: The implementations here should be similar to ones you've seen before in the readings or comprehension questions.
"""
from typing import Union

def num_positives(obj: Union[int, list]) -> int:
"""Return the number of positive integers in .

Remember, 0 is *not* positive.

>>> num_positives(17)
1
>>> num_positives(-10)
0
>>> num_positives([1, -2, [-10, 2, [3], 4, -5], 4])
5
"""
count = 0
if (obj == int) and (obj > 1):
count += 1
else:
for item in obj:
count += num_positives(item)
return count

def nested_max(obj: Union[int, list]) -> int:
"""Return the maximum integer stored in nested list .

Return 0 if is an empty list.

Precondition: all integers in are positive.

>>> nested_max(17)
17
>>> nested_max([1, 2, [1, 2, [3], 4, 5], 4])
5
"""

def max_length(obj: Union[int, list]) -> int:
"""Return the maximum length of any list in nested list .

The *maximum length* of a nested list is defined as:
1. 0, if is a number.
2. The maximum of len(obj) and the lengths of the nested lists contained
in , if is a list.

>>> max_length(17)
0
>>> max_length([1, 2, [1, 2], 4])
4
>>> max_length([1, 2, [1, 2, [3], 4, 5], 4])
5
"""
pass

if __name__ == '__main__':
import doctest

doctest.testmod()

import python_ta

python_ta.check_all()

Answer rating: 100% (QA)

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