Question: ( 1 ) if n < m then return 0 , n ( 2 ) let q : = 0 ( 4 ) let r

(1) if
n
<
m
then return
0
,
n
(2) let
q
:=
0
(4) let
r
:=
n
(4) repeat
---(a) let
r
:=
r
m
---(b) let
q
:=
q
+
1
(5) until
r
<
m
(6) return
q
,
r
What does the algorithm return when the input is
n
:=
8
and
m
:=
7
?

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