Question: 1 In each case, multiply out to obtain a sum of products: (Simplify where possible) (a) A'bc'd+(a'+bc)(a+c'd')+bc'd+a'bc

1 In each case, multiply out to obtain a sum of

1 In each case, multiply out to obtain a sum of products: (Simplify where possible) (a) A'bc'd+(a'+bc)(a+c'd')+bc'd+a'bc

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