Question: 1 . In the amplifier circuit above, let's consider the AC source labeled V 3 to be an object with very low output impedance and

1. In the amplifier circuit above, let's consider the AC source labeled V 3 to be an object with very low output impedance and let the frequency be fixed at 100 kHz . The load resistor RL will represent the input impedance of some other circuit that is going to receive the output of this amplifier.
a.(5 pts) Using LTspice to do the measurements, make a plot of the current (amplitude) drawn from V3 as a function of the voltage amplitude of V3. From your plot, calculate the effective input impedance of this amplifier for low signal levels and a frequency of 100 kHz .
b.(5 pts) At a fixed amplitude for V3, vary RL and make a plot of Vout as a function of RL. If the output impedance (Zout) of this amplifier circuit were zero, then Vout would not vary as RL is varied. However, if the output impedance is not zero, then a voltage divider is formed with Zout and RL in series and Vout is the voltage across RL. When RL=Zout, Vout should be half of what it is when RL >> Zout. Based on your data, what is the output impedance of this amplifier at 100 kHz ?
c.(3 pts) Given your values of Zin and Zout for this amplifier, would you say that it is a pretty good instrument or not? Why?
1 . In the amplifier circuit above, let's

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