1. is the question correctly or not.

2. If not, explain in as much detail as possible what was done incorrectly and what the correct answer should have been.

A. For a pizza store,37% of customers order Classic crust, 41 customers order cheesy crust, 2% of customers order gluten-free, and 20% of customer order puff crust. What is the probability that a randomly selected customer in this pizza store orders a classic crust or a cheesy crust pizza?

B. In a group of 25 newborn dogs, 18 enjoyed barking at the neighbors, 16 enjoyed eating lunch, and 10 enjoyed both. If one newborn dog is selected randomly, find the probability that it enjoys barking at the neighbors or eating lunch.

A. Since the events are mutually exclusive when asked to find the probability of cheesy or classic crust we can add the probabilities of the individual events.

P(classic crust or cheesy crust) = P(classic crust) + P(cheesy crust)

P(classic crust or cheesy crust) = 0.37 + 0.41

P(classic crust or cheesy crust) = 0.78

B. Since the events aren't mutually exclusive we have to use the formula that accounts for the intersection of the two events

P(enjoys barking or eating lunch)= P(enjoys barking) + P(enjoys lunch) - P(enjoys barking enjoys)

P(enjoys barking or eating lunch) = 18/25 + 16/25 - 10/25

P(enjoys barking or eating lunch) = 24/25 = 0.96