Question: 1. Let f : [-2, 2] -> [-4, 4]; f(x) = x2, find (a) (1 point) f-1((0, 4)) (b) (1 point) f-'(f({2})) Just give the

1. Let f : [-2, 2] -> [-4, 4]; f(x) = x2, find (a) (1 point) f-1((0, 4)) (b) (1 point) f-'(f({2})) Just give the answer. 2. Write a rigorous proof that f : [1, 6 -> 3, 13]; f(x) = 2x + 1 is bijective. For that, you must prove three parts: that f is well defined, injective and surjective

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