#1 options - population, sample, statistic

#2 options- standard deviation, proportion, mean

#3 options- all, 32

As part of a project to develop better lawn fertilizers, a research chemist wanted to determine the mean weekly growth rate of Kentucky bluegrass, a common type of grass. A random sample of 32 blades of grass was measured, and the amount of growth in one week was recorded. The sample mean weekly growth was found to be 0.52 inches. Assuming that the population standard deviation is 0.15 inches and that the weekly growth is normally distributed, estimate with 99% confidence the mean weekly growth of Kentucky bluegrass. Round to three decimal places. Complete the following sentence to provide an interpretation of the confidence interval in the context of the problem: weekly growth of (Click to select) v blades of Kentucky We are 99% confident that the (Click to select) v (Click to select) bluegrass is between and inches. As part of a project to develop better lawn fertilizers, a research chemist wanted to determine the mean weekly growth rate of Kentucky bluegrass, a common type of grass. A random sample of 32 blades of grass was measured, and the amount of growth in one week was recorded. The sample mean weekly growth was found to be 0.52 inches. Assuming that the population standard deviation is 0.15 inches and that the weekly growth is normally distributed, estimate with 99% confidence the mean weekly growth of Kentucky bluegrass. Round to three decimal places. Complete the following sentence to provide an interpretation of the confidence interval in the context of the problem: weekly growth of (Click to select) v blades of Kentucky We are 99% confident that the (Click to select) v (Click to select) bluegrass is between and inches