$(1$ point$)$ Compute the following limits using L'Hospital's rule if appropriate. Use INF to denote $$ and MINF to denote $-.$

$\underset{x1}{lim}\frac{8^x-8}{x^2-1}=$

$\underset{x}{lim}\frac{ta{n}^{-1}(x)}{(\frac{1}{x})-8}=$