Question: {1 point) Consider the function f(::, y} = (8 7 :2} sin{y) Suppose S is the surface 2. = z, y). (a) Find a vector

 {1 point) Consider the function f(::, y} = (8\" 7 :2}

{1 point) Consider the function f(::, y} = (8\" 7 :2} sin{y) Suppose S is the surface 2. = z, y). (a) Find a vector which is perpendicular to the level curve of I through the point (5,3) in the direclion in which 3' decreases most rapidiy. vector: l l (b1 Suppose if = 43'. + 3} + GE is a vector in 3'space which is tangent to the surface S at the point P lying on the surface above (5, 3). What is a? a. z |

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