(1 point) Consider the initial value problem dy 5 + 2x +y, y(0) = -3. Since this is a linear first order DE, it can be solved exactly and the value of the solution at c = 1 is y(1) exact = For this DE we don't need to use Euler's method, but let's do so anyway. We can use the known exact solution to compute the error of Euler's method. You will find that the error is approximately proportional to the step size h. Using h = 0.1, y(1)Euler = The error of this approximation is ly(1) Euler - W/(1)exact| = Using h = 0.05, y(1) Euler = The error of this approximation is |y(1) Euler - W/(1)exact| = Using h = 0.025, y(1)Euler = The error of this approximation is |y(1) Euler - V(1)exact| =