Question: (1 point) Let f(x) = -3 + -1x + 2x2. If h # 0, then the difference quotient can be simplified as f(x + h)

 (1 point) Let f(x) = -3 + -1x + 2x2. If
h # 0, then the difference quotient can be simplified as f(x

(1 point) Let f(x) = -3 + -1x + 2x2. If h # 0, then the difference quotient can be simplified as f(x + h) -f(x) = Ah + Bx + C, h where A, B, and C are constants. (Note: It's possible for one or more of these constants to be 0.) Find the constants. A = B = , and C = Use the simplified expression to find f (x) = lim f(x + h) - f(x) = h-0 h Finally, find each of the following: f'(1) = f' (2) = , and f'(3) =

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