Question: (1 point) Let f(x) = x2 - 4x - 5 for x > 2. Find the value of df- 1 dx at the point x

(1 point) Let f(x) = x2 - 4x - 5 for
x > 2. Find the value of df- 1 dx at the

(1 point) Let f(x) = x2 - 4x - 5 for x > 2. Find the value of df- 1 dx at the point x = -8 = f(3). df-1 dx x=-8

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