Question: 1 point ) Solve the separable differential equation 3 2 2 + 1 = 0 3 x 2 yx 2 + 1 dydx = 0

1 point) Solve the separable differential equation
322+1=03x2yx2+1dydx=0
subject to the initial condition: (0)=6y(0)=6.

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