(1 point) Suppose that f(8) = 5, f'(8) = 3, g(8) = 8, and g'(8) (fg)'(8)...

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(1 point) Suppose that f(8) = 5, f'(8) = 3, g(8) = 8, and g'(8) (fg)'(8) = (f/g)'(8) = (g/f)'(8) = = 4. Then (1 point) Suppose that f(8) = 5, f'(8) = 3, g(8) = 8, and g'(8) (fg)'(8) = (f/g)'(8) = (g/f)'(8) = = 4. Then

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For finding fg8 we use product rule of differentiability that is fg8 f8g8 f8g8 All values ... View the full answer