Question: ( 1 point ) Suppose y = s i n ( - 4 x 2 - 3 x - 1 ) . We can write

(1 point) Suppose y=sin(-4x2-3x-1). We can write y=sin(u), where u= The Leibnitz notation for the chain rule is dydx=dydu*dudx.
The factors are dydu=(written as a function of u) and dudx=
Now substitue in the function of x for u to get
dydx=(written as a function of x).
( 1 point ) Suppose y = s i n ( - 4 x 2 - 3 x - 1

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