$(1$ point$)$ Suppose $y=sin(4x^2-2x2).$ We can write $y=sin(u),$ where $u=$

$$ The Leibnizz notation for the chain rule is $\frac{dy}{dx}=\frac{dy}{du}*\frac{du}{dx}.$ The factors are $\frac{dy}{du}=($written as a function of $u)$ and $\frac{du}{dx}=$

$$ Now substitue in the function of $x$ for $u$ to get

$\frac{dy}{dx}=($writien as a function of $x).$

Note: You can earn partial credi on this problem.