$(1$ point$)$ The volume of the solid obtained by rotating the region enclosed by

$y=\frac{1}{x^2},y=0,x=3,$ and $x=9$

about the line $y=-1$ can be computed using the method of disks or washers via an integral

$V={\displaystyle \underset{a}{\overset{b}{}}}(((\frac{1}{x^2}+1{)}^2)-1^2)$

with limits of integration $a=$ and $b=$