Question: (1 point) Transform the differential equation 3y + 33y - 3y' - 33y = 6e-It y(0) = 0 y' (0) = 0 y(0) = 1

(1 point) Transform the differential equation 3y" + 33y" - 3y' - 33y = 6e-It y(0) = 0 y' (0) = 0 y"(0) = 1 into an algebraic equation by taking the Laplace transform of each side. Use Y for the Laplace transform of y, (not Y(s)). Therefore Y = 1 8- + + s+1 Taking the inverse Laplace transform we get y =

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