$[-/1$ Points$]$

SCALCCC$55\mathrm{.}2\mathrm{.}503.$XP$.$

Use the Midpoint Rule with the given value of $n$ to approximate the integral. Round the answer to four decimal places.

$M_5=$

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$7.[-/1$ Points$]$

SCALCCC$55\mathrm{.}2\mathrm{.}021.$MI$.$

$8.[-/1$ Points$]$

SCALCCC$55\mathrm{.}2\mathrm{.}507.$XP$.$

Use the form of the definition of the integral given in the theorem to evaluate the integral.

${\displaystyle \underset{1}{\overset{7}{}}}(x^{2}6x-9)dx$