$[-/1$ Points$]$

SCALCET$94\mathrm{.}4\mathrm{.}008.$

ASK YOUR TEACHER

Find the limit$.$ Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it$.$

$\underset{x3}{lim}\frac{x-3}{x^2-9}$

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$2.[-/1$ Points$]$

SCALCET$94\mathrm{.}4\mathrm{.}009.$