$[-/1$ Points$]$

$$ SERCP$1125.$A$.$P$\mathrm{.}060.$

A person with a nearsighted eye has near and far points of $18$ cm and $28$ cm $,$ respectively.

$($a$)$ Assuming a lens is placed $2\mathrm{.}0$ cm from the eye, what power must the lens have to correct this condition?

$$ diopters and the eyeglass lens require slightly different powers because they are at different distances from the eye.

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$P=$ new near point

$=$ diop

$cm$

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