1.

Set 'x': 1 5 .'_ Does it work? El YES! (a) Use the sliders and set I = 1 and E = .5 What is the largest value that works for :5? C] (Hint: check the box that says "Does it work" and use your arrow keys to move the slider one one-hundredth at a time) (b) Use the sliders and set 3 = -5 and set E = .3 The largest value that works for 5 is 5 = .22. (Notice as you make (5' > .22 , the values of the function are red, and when the values of 5 E .22 the values of the function are green} Why doesn't it work when 5 i} .22? 0 When evaluating the function using values of it outside the interval [ .22, .22], the value of the function doesn't lie within epsilon of f{ .5] C) When evaluating the function using values of it outside the interval [ .72, .23], the value of the function doesn't lie within epsilon of H .5) C' When evaluating the function using values of x outside the interval [ .5, .5], the value of the function doesn't lie within epsilon of .5) Use the graph above {click the double arrows next to the gear to enlarge the graph] or visit the following this desmos link. Iii-l Interact with the graph in order to determine a 5 so that if l: {1| {1 5, then \"(3) Ll at: E . Please 2 make sure your response is accurate to within three decimal places. Let 3"[3] = 2'3, and let I } 1, and suppose that E = .001. Determine 5 so that if II {1| if. 5 , then Im] LI s: E