1. Solve forx from the following:x2(x1)(x2)=0

2. When finding the square root of a positive natural number, the solution has both a negative and positive component unless otherwise stated. Given this information andx2=25. Find the values ofx by taking square roots on both sides.

3. Find the solution to the quadratic equation given asx2+6x+5=0 . Hint: factorize, equate to zero and solve.

4. In the equation x(x5)=0, there are two solutions. By simple linear comparison, find the two values ofx that satisfy the equation.

5. Multiply term by term from(x+2)(x+5)=0 to obtain a quadratic equation of the form x2+bx+c=0.

6. Quadratic Equations : With quadratic equation given as: ax + bx + c = 0, the leading coefficient = a, cannot be equal tozero. Briefly explain why.