Question: (1) Suppose that the function y_(1)(t) is a solution of y^('')+a_(1)y^(')+a_(0)y=cos(2t). (2) Also suppose that the function y_(2)(t) is a solution of y^('')+a_(1)y^(')+a_(0)y=0.

(1) Suppose that the function

y_(1)(t)

is a solution of\

y^('')+a_(1)y^(')+a_(0)y=cos(2t).

\ (2) Also suppose that the function

y_(2)(t)

is a solution of\

y^('')+a_(1)y^(')+a_(0)y=0.

\ Use the Superposition Theorem 2.1.6 to decide which of the following statements are true.\ A.

3y_(1)

solves

(1)

\ B.

2y_(2)

solves (2)\ C.

-y_(1)+y_(2)

solves (1)\ D.

y_(1)+y_(2)

solves

(1)

\ E.

y_(1)+y_(2)

solves (2)\ F.

y_(1)+4y_(2)

solves (1)\ G. None of the Above\ Note: Select all that applies.

 (1) Suppose that the function y_(1)(t) is a solution of\ y^('')+a_(1)y^(')+a_(0)y=cos(2t).\

(1) Suppose that the function y1(t) is a solution of y+a1y+a0y=cos(2t). (2) Also suppose that the function y2(t) is a solution of y+a1y+a0y=0 Use the Superposition Theorem 2.1.6 to decide which of the following statements are true. A. 3y1 solves (1) B. 2y2 solves (2) C. y1+y2 solves (1) D. y1+y2 solves (1) E. y1+y2 solves (2) F. y1+4y2 solves (1) G. None of the Above Note: Select all that applies

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