1. The distribution line below uses ACSR 4/0 conductors (Linnet) and operates at 60 Hz. Use...

  

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1. The distribution line below uses ACSR 4/0 conductors (Linnet) and operates at 60 Hz. Use the conductor tables A4 for the following: a. Compute the resistance per phase per 1000 ft (at 25 deg C and 60 Hz). b. What is the current carrying capacity of the conductor? c. Without transposing the line, compute the self-inductance for each phase per 1000 ft. Use the logarithmic formulas. d. Compute the inductance per phase per 1000 ft for the same line if you assume full transposition. -10 ft- T TABLE A.4 Characteristics of aluminum cable, steel, reinforced (Aluminum Company of America)-ACSR Aluminum Steel Copper Weight Equivalent Mils or Se (pounds a Resistance (Ohms per Conductor per Mile) 50°C (122°F) Current Approx. 5% Capacity! 25°C (77°F) Smali Currents Outside Current Carving (amps) Б AWG (pounds) mile! de 25 Hz 50 Hz 60 Hz dc 25 Hz 50 Hz 60 Hz 0 Hz 100450 0.337 10.0487 0.342 67 300 0.0511 49 800 0.348 60 300 0.0505 344 51000 0.0098 0.355 56 000 10777 1380 00587 00588 0.0590 0.359 0237 9 099 1 340 0.0618 0.0619 0.0621 1300 0.0052 0.0653 0.0655 0.900 0.0591 0.0646 0.0656 0.0675 0.0684 0622 00680 0.0690 0.0710 0.0720 0.362 0.0656 0.0718 007290029900000 0.07340073500737 0073800808 0.0819 0.0840 0.0851 0.372 0.0783 00784 0.0786 0.0788 0.0862 0.0872 0.0894 0.0906 0.376 9621 1200 8082 160 700 000 40 200 0.083900840 0.08420.084400924 0.0935 0.0957 0.0969 0.300 2012 080 600.000 34 200 479 1010 0 390 00979 0.0980 0.0981 0.0982 0 1078 0 1088 01118 01128 0104 0.104 900.000 54 32 300 6112 0.393 970 950 874 500 54 31 400 5940 0.107 0.104 0104 01145 0.1155 0.1175 0.1185 0.107 0107 0108 01178 0.1188 0.1218 01228 0.118 10.118 Uitg 1288 01308 01358 0.1378 0:000 0.401 795.000 54 28 500 5 399 795 000 900 0117 0.117 0.117 0117 01288 0.1288 01288 01288 0.399 0.1360 0.0977 795 000 715 500 31 200 500 000 38 400 450000 26300 5770 9517 1899 0.117 0.1151 0.1290 115.500 666 600 54 450.000 34.600 419.000 24 500 01111 1.000 636 000 54 0.108⁹ 0.977 23600 400 000 100.000 1616 213 626.000 0.0874 1019 31.500 22 500 605 000 0.1059 0.953 380 500 109 605 000 0.1186 0.966 380 500 24 100 4391 990 300 0.1138 0.927 350 000 22 400 4039 27 200 4 588 18491 1859 0.1859 0.1859 556 500 477 000 477.000 397 500 937 300 0.1362 0.953 20.1054 0.858 0.1261 0.883 0765 300 000 19430 8462 300 000 3500 3933 2005 250000 0.299 0.000 01151 0.1151 0.0855 0.721 336 400 336 400 470 4050 7040 0.1059 0.741 714 0.1138 0.1059 0.1074 01013 100.30 0.0835 0700 198 700 16420 0242 200.000 20 266 800 26 2472 936 10798 0.642 3/0 11 250 *Based on copper 97% aluminum 61% conductivity. *For conductor at 75 C. air at 25°C wind 1.4 miles per hour (2 ft/sec), frequency - 60 Hz Current Approx 75% Capacity is 75% of the "Approx. Current Carrying Capacity in Amps" and is approximately the current which will produce 50°C conductor temp. (25°C rise) with 25°C air temp., wind 1.4 miles per hour pro 12238 Looc cso ====== 113000 54 222252 لا لا لا لا لا لا لله الله لا لا لا لا 223223 322322 ~2~22 22222 DURA forho 010:0 01819 0.1735 0.1602 0.1456 0.1716 - oooooo ----- 10 10 mm OO MON 00000 -ho 0000 w ---- 0.1214 T 0000 - 7616 105 111 ar 0.1111 min 0.0 - GO010 --- 20 01525 co 00000 FFFF BONNE 10 10 10 3 is 1960'0 000 735 1.762 100€ 1.545 1.506 1,465 267 338 GEZI 1.196 1.162 146 1.093 1.108 1140 1.036 +601 00 000 009 000 098 Love com > 00 7ttr7 OC OC 962 a X DO O 00000 00 F 000 00 22 5 ooooo C لما لما OC 131 0131 140 0.141 +44 000000 61 ga 32 000 D D Ooo 1711 4556 -33 000000 पंप 0000 000C 225 is 00000 45 6441 m st - 9 P A B77548 -- 000000 44555 OOOO oo SAA == In 1618 0.1638 O === AA 450 P 2 00 NN 00 00 00 SE 000 711525 oooo00 ---- 1778 oooo0 ------ ∞ ∞ ∞ 22200 8550 ОФФ Ф a Inductive hoaciance onductor pe mile at 1 ft spacing sauna 000 ( 0000 ooooo00 00:0 2105 0 299 0.412 0.414 0406 0.417 0.415 3.420 J.415 1.430 000000 00000 6766 SUPE 0.451 3.443 423 ooooo 10:04 mm 1 DIN MAN HA IN 1. The distribution line below uses ACSR 4/0 conductors (Linnet) and operates at 60 Hz. Use the conductor tables A4 for the following: a. Compute the resistance per phase per 1000 ft (at 25 deg C and 60 Hz). b. What is the current carrying capacity of the conductor? c. Without transposing the line, compute the self-inductance for each phase per 1000 ft. Use the logarithmic formulas. d. Compute the inductance per phase per 1000 ft for the same line if you assume full transposition. -10 ft- T TABLE A.4 Characteristics of aluminum cable, steel, reinforced (Aluminum Company of America)-ACSR Aluminum Steel Copper Weight Equivalent Mils or Se (pounds a Resistance (Ohms per Conductor per Mile) 50°C (122°F) Current Approx. 5% Capacity! 25°C (77°F) Smali Currents Outside Current Carving (amps) Б AWG (pounds) mile! de 25 Hz 50 Hz 60 Hz dc 25 Hz 50 Hz 60 Hz 0 Hz 100450 0.337 10.0487 0.342 67 300 0.0511 49 800 0.348 60 300 0.0505 344 51000 0.0098 0.355 56 000 10777 1380 00587 00588 0.0590 0.359 0237 9 099 1 340 0.0618 0.0619 0.0621 1300 0.0052 0.0653 0.0655 0.900 0.0591 0.0646 0.0656 0.0675 0.0684 0622 00680 0.0690 0.0710 0.0720 0.362 0.0656 0.0718 007290029900000 0.07340073500737 0073800808 0.0819 0.0840 0.0851 0.372 0.0783 00784 0.0786 0.0788 0.0862 0.0872 0.0894 0.0906 0.376 9621 1200 8082 160 700 000 40 200 0.083900840 0.08420.084400924 0.0935 0.0957 0.0969 0.300 2012 080 600.000 34 200 479 1010 0 390 00979 0.0980 0.0981 0.0982 0 1078 0 1088 01118 01128 0104 0.104 900.000 54 32 300 6112 0.393 970 950 874 500 54 31 400 5940 0.107 0.104 0104 01145 0.1155 0.1175 0.1185 0.107 0107 0108 01178 0.1188 0.1218 01228 0.118 10.118 Uitg 1288 01308 01358 0.1378 0:000 0.401 795.000 54 28 500 5 399 795 000 900 0117 0.117 0.117 0117 01288 0.1288 01288 01288 0.399 0.1360 0.0977 795 000 715 500 31 200 500 000 38 400 450000 26300 5770 9517 1899 0.117 0.1151 0.1290 115.500 666 600 54 450.000 34.600 419.000 24 500 01111 1.000 636 000 54 0.108⁹ 0.977 23600 400 000 100.000 1616 213 626.000 0.0874 1019 31.500 22 500 605 000 0.1059 0.953 380 500 109 605 000 0.1186 0.966 380 500 24 100 4391 990 300 0.1138 0.927 350 000 22 400 4039 27 200 4 588 18491 1859 0.1859 0.1859 556 500 477 000 477.000 397 500 937 300 0.1362 0.953 20.1054 0.858 0.1261 0.883 0765 300 000 19430 8462 300 000 3500 3933 2005 250000 0.299 0.000 01151 0.1151 0.0855 0.721 336 400 336 400 470 4050 7040 0.1059 0.741 714 0.1138 0.1059 0.1074 01013 100.30 0.0835 0700 198 700 16420 0242 200.000 20 266 800 26 2472 936 10798 0.642 3/0 11 250 *Based on copper 97% aluminum 61% conductivity. *For conductor at 75 C. air at 25°C wind 1.4 miles per hour (2 ft/sec), frequency - 60 Hz Current Approx 75% Capacity is 75% of the "Approx. Current Carrying Capacity in Amps" and is approximately the current which will produce 50°C conductor temp. (25°C rise) with 25°C air temp., wind 1.4 miles per hour pro 12238 Looc cso ====== 113000 54 222252 لا لا لا لا لا لا لله الله لا لا لا لا 223223 322322 ~2~22 22222 DURA forho 010:0 01819 0.1735 0.1602 0.1456 0.1716 - oooooo ----- 10 10 mm OO MON 00000 -ho 0000 w ---- 0.1214 T 0000 - 7616 105 111 ar 0.1111 min 0.0 - GO010 --- 20 01525 co 00000 FFFF BONNE 10 10 10 3 is 1960'0 000 735 1.762 100€ 1.545 1.506 1,465 267 338 GEZI 1.196 1.162 146 1.093 1.108 1140 1.036 +601 00 000 009 000 098 Love com > 00 7ttr7 OC OC 962 a X DO O 00000 00 F 000 00 22 5 ooooo C لما لما OC 131 0131 140 0.141 +44 000000 61 ga 32 000 D D Ooo 1711 4556 -33 000000 पंप 0000 000C 225 is 00000 45 6441 m st - 9 P A B77548 -- 000000 44555 OOOO oo SAA == In 1618 0.1638 O === AA 450 P 2 00 NN 00 00 00 SE 000 711525 oooo00 ---- 1778 oooo0 ------ ∞ ∞ ∞ 22200 8550 ОФФ Ф a Inductive hoaciance onductor pe mile at 1 ft spacing sauna 000 ( 0000 ooooo00 00:0 2105 0 299 0.412 0.414 0406 0.417 0.415 3.420 J.415 1.430 000000 00000 6766 SUPE 0.451 3.443 423 ooooo 10:04 mm 1 DIN MAN HA IN

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Solution Griven the distribution line below has According ACSIR 410 Conductors to the ... View the full answer