1.

The figure shown below is a uniform meter stick where the fulcrum (pivot) is at the 24-cm mark when a mass m, = 293 grams is attached to the meter stick at the 10-cm mark. The center of gravity of the meter stick is at the 50-cm mark. What is the mass of the meter stick, in grams, if the system is in rotational equilibrium (i.e., the clockwise and counterclockwise torques are equal)? Please round your answer to one decimal place. 10 20 30 40 50 60 70 80 90 m1One of the following is a condition for the rotational equilibrium of a rigid body: O the clockwise and the counter clockwise torques have to be equal in magnitude. O all the external forces have to be equal to all the external torques. O all external forces acting on the rigid body have to be zero O the mass of the rigid body has to be the same as all other masses. O the center of gravity and the center of mass have to coincide