1. The fixed point scheme is in such a way that xr+1 = g(xr). 2. Given...

 

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1. The fixed point scheme is in such a way that xr+1 = g(xr). 2. Given f(x) = x2 - 2x - 3, 3. Generate all the possible schemes by splitting f (x). (4 Marks) 4. (Using the convergence Criterion, Determine which scheme is convergent to the zero of f (x). (4 Marks) 5. Use the bisection method to approximate the root of x2 = 3 on [1, 2] (5 Marks) 6. State on advantages and disadvantages of the Bisection method of finding a zero of f (x) = 0. (2 Marks) 1. The fixed point scheme is in such a way that xr+1 = g(xr). 2. Given f(x) = x2 - 2x - 3, 3. Generate all the possible schemes by splitting f (x). (4 Marks) 4. (Using the convergence Criterion, Determine which scheme is convergent to the zero of f (x). (4 Marks) 5. Use the bisection method to approximate the root of x2 = 3 on [1, 2] (5 Marks) 6. State on advantages and disadvantages of the Bisection method of finding a zero of f (x) = 0. (2 Marks)