1) The initial transportation cost is *

$643

$436

$599

None of the answers.

$595

2) Using the Method of Multipliers, the values of U1, U2, U3, & U4 are respectively *

0, -1, 1, 12

0, 4, -1, 15

0, 5, -1, -5

0, -3, -1, 2

None of the answers.

3) Using the Method of Multipliers, the values of V1, V2, V3, & V4, are respectively *

1, 8, 20, 27, 14

5, 1, 11, 13, 14

5, 10, 11, 13, 14

None of the answers.

5, 1, 1, 13, 14

4) The 1st entering variable is *

X24

None of the answers.

X41

X14

X13

4) The 1st closed loop consists of cells *

None of the answers.

X42, X23, X33, X34

X21, X23, X33, X34

X24, X23, X33, X34

X24, X23, X33, X43

5) The value of 1 is *

6

None of the answers.

2

8

4

6) Is the resulting Transportation Matrix "Optimal" ? *

No, since there are still reduced costs

None of the answers.

Yes, since all reduced costs are

Yes, since all reduced costs are > 0.

No, since there are still reduced costs > 0.

7) The 2nd closed loop consists of cells *

X31, X11, X12, X22, X24, X44

None of the answers.

X31, X11, X12, X22, X24, X34

X11, X15, X12, X22, X24, X34

X13, X11, X12, X22, X24, X34

8) The transportation cost resulting from the 2nd iteration is: *

$563

$536

None of the answers.

$202

$320

9) The Minimum Transportation Cost resulting from the Optimal Matrix, equals *

None of the answers.

$345

$817

$718

$543

I need the answers in 30 minutes please.

Z = . The following LP model represents the Transportation Model at Bozarth Co: Minimize z = 5x11 + 10x12 + 7x13 + 8x14 + 12x15 + 14x21 + 15x22 + 16x23 + 9x24 + 11x25 + 9x31 + 20x32 + 10x33 + 12x34 + 13x35 + 15x41 +14x42 + 16x43 + 8X44 + 9x45 Subject to: X11 + x12 + x13 + X14 + X15 18 X21 + x22 + x23 + x24 + X25 = 13 X31 + x32 + x33 + X34 + X35 = 17 X41 + x42 + x43 + x44 + X45 + 12 X11 + x 21 + X31 + X41 15 X12 + X22 + x32 + x42 12 X13 + x23 + X33 + X43 12 X14 + X24 + X34 + X 44 10 X15 + X25 + X35 + X45 11 . 1 Xij 20