Question: 1. The modified equation for flow over a rectangular weir is given as: q = 3.33 (L-0.200 ho)h25 where, q = volumetric flow rate (fi/s)

 1. The modified equation for flow over a rectangular weir is

given as: q = 3.33 (L-0.200 ho)h25 where, q = volumetric flow

rate (fi/s) L = crest height (ft) h = weir head (ft)

c) What are the units of the numbers 3.33 and 0.200 by

1. The modified equation for flow over a rectangular weir is given as: q = 3.33 (L-0.200 ho)h25 where, q = volumetric flow rate (fi/s) L = crest height (ft) h = weir head (ft) c) What are the units of the numbers 3.33 and 0.200 by Change the equation such that q will be in m/hr, L in m, and ho in m. 2. A solution of HCl in water is flowing in a pipe at a rate of 10 kgmoles solution/min. The density of the solution is 1160 kg/m, and the concentration of HCl is 200 g/L solution. Calculate: a. the concentration of HCl in wt%. b. the average molecular weight of the solution. (MW: H=1, O=16, C1==35.5) c. the flow rate of solution in ft/min. 3. Find the following: a) 10.31 mm/hr in ft/s b) number of pounds in 3.0 gmoles of N2 c) (9.022 * 3.11) + 1500 (122) to the correct number of significant figures 42.1 d) The concentration of magnesium (mass %) in seawater if its PPM is 1272. 4. The absolute pressure on a submarine moving below the surface of the sea is 2.20 atm. At what depth below the surface of water is it moving? Given: the barometric pressure is 755 mmHg and the density of water is 1035 kg/m

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemical Engineering Questions!