Question: 1) The random variable x is normally distributed with mean = 18 and standard deviation = 7.6. Find the following ( In each case, draw

1) The random variable x is normally distributed with mean = 18 and standard deviation = 7.6. Find the following (In each case, draw a sketch).

a) P(x > 20)

b) P(0 < x < 5)

c) Find the value of x that has 88.3% of the distribution's area to its left.

d) Find the value of x that has 64.8% of the distribution's area to its right.

2) The mean amount of money that U.S. adults spend on food in a week is $151 and the standard deviation is $49. Random samples of size 50 are drawn from this population and the mean of each sample is determined. (draw a sketch in b and c)

a) Find the mean and standard deviation of sampling distribution of sample means.

b) What is the probability that the mean amount spent on food in a week for a certain sample is more than $160?

c) What is the probability that the mean amount spent on food in a week for a certain sample is between $135 and $150?

3) In a survey of 2383 U.S. adults, 1073 think that there should be more government regulation of oil companies.

a) Find the point estimate for the population proportion p of U.S. adults who think that there should be more government regulation of oil companies.

b) Construct a 95% confidence interval for the population proportion. Interpret your results.

c) Find the minimum sample size needed to estimate the population proportion at the 99% confidence level when the margin of error is 3%.

4) The data set represents the weights (in grams) of 10 randomly selected adult male fox squirrels from a forest. Assume the weights are normally distributed.

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a) Find the sample mean and the sample standard deviation (you will need to use sections 3.2 and 3.3 to find the sample mean and the sample standard deviation).

b) Construct a 95% confidence interval for the population mean. Interpret your results.

c) Construct a 99% confidence interval for the population variance.

d) Construct a 99% confidence interval for the population standard deviation.

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