1) Translate the following C code to LEGv8 (a version of ARMv8). Assume the variables f, g, h, i, and j are assigned to registers X0, X1, X2, X3, and X4. Assume the base address of arrays A and B are in X6 and X7, and that each element in the arrays takes up 8 bytes. Do these using only the ADD, SUB, and the other bitwise logical instructions.

A) h = f * 4;

B) Do this with only 2 instructions:

j = i * 7;