$1.$ Two points, A and B$,$ are located in $2$D Cartesian space with flow conditions known to be supersonic, isentropic$,$ and irrotational.$$ Assume this gas to be calorically perfect Air.

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Point A$,$ located at $(0\mathrm{.}4,0\mathrm{.}8),$ has a Mach number, MA$=3\mathrm{.}5,$ static pressure, PA$=2$ kPa, and flow velocity angle, qA$=+15$O$.$

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Point B$,$ located at $(0,0),$ has a Mach number, MB$=1\mathrm{.}75,$ static temperature, TB$=350$ K$,$ and flow velocity angle qB$=-3$O$.$

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As in class, q is defined relative to the X$-$axis $($positive counterclockwise$).$ The intersection of the C$-$ characteristic line from Point A and the C$+$ characteristic line from Point B intersect at a new point C$.$ While rounding all calculations to the second decimal, Find:

$($a$)$ the flow angle at Point C$,$C$($degrees$).$

$($b$)$ the Mach number at Point C$,$ MC$.$

$($c$)$ the horizontal location of Point C in Cartesian space, xC$.$

$($d$)$ the vertical location of Point C in Cartesian space, yC$.$

$($e$)$ the static pressure, PC$,$ at Point C $($kPa$).$

$($f$)$ the static temperature, TC$,$ at Point C$.$

$($g$)$ the velocity magnitude at Point C

$($h$)$ the horizontal velocity component at Point C$,$ uC

$($i$)$ the vertical velocity component at Point C$,$ vC

I alreadly have the answers to parts $($a$)$ and $($b$),$ the answer to $($a$)$ is $25\mathrm{.}63$ degrees and the answer to $($b$)$ is $2\mathrm{.}91$

I just need the rest