Question: 1. We have the following C++ program segment double x, U O., for (x=1.; x=1 .; D=0., M-5000. ; x+=1.) U +, pow (0.01*x, x-=1.)
1. We have the following C++ program segment double x, U O., for (x=1.; x=1 .; D=0., M-5000. ; x+=1.) U +, pow (0.01*x, x-=1.) D += pow (0.01*x, 2.2); 2.2); a What is displayed by this program? Give a detailed explanation of your answer. What result would you expect if M=3.0 and why
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