1. When an elevator is moving, normal force on the person by the floor is 520 M. Mass of person is 62 kg. A) Determine the regular weight of the person . B) By drawing free body diagram for the Pearson and direction of acceleration, calculate the acceleration of the elevator. 2. A lawnmower is pushed with a force F (80 N) at an angle theta =37.0 degrees as shown in the figure . The mass of the more is 15 KG. The coefficient of kinetic friction between the mower and the lawn is 0.27. The mower is accelerating horizontally on the lawn. A) try the free body diagram of the lawn, showing the direction of acceleration. B) by using the free body diagram and applying newtons second law, -Determine the normal force on the mower -Determine the acceleration of the mower 3) a 50 KG object is put on an incline plane( theta = 30 degrees) as shown in the figure . The coefficient of kinetic friction between the object on the surface is 0.22. The object slides with an acceleration down the incline. a) Draw the free body diagram of the object showing x and y components of the forces and acceleration direction . b) By using free body diagram and applying Newtons 2nd law , determine the normal force on the box . c) By using free body diagram and applying newtons 2nd law , determine the acceleration of the object sliding down the incline . 4) Two masses m1 (2.2 kg) and m2 (3.2kg) are hung from string over the pulley as shown in the diagram . If the system is released, M1 goes up at him to go down with the same magnitude of acceleration. The force of tension on both sides of the string remains the same by drawing to separate free body diagram for M1 and M2 determine the acceleration and fourth of tension. 5. Radius of a Ferris wheel is 10 m. a) By drawing a free body diagram and applying newtons second law, determine the speed of the wheel at which the passenger in the car will feel completely weightless when he is at the top most point . b) the speed of the wheel at the top is 5.0 M/S. By drawing free, body diagram and apply newtons laws determine the parent weight of the passenger 65 KG at the top most point. 6. State newtons law of universal gravitation, using the word, directly proportional and inversely proportional. b) using newtons, universal law of gravitational and concept of Centripedal force, derive an expression for distance, R of geosynchronous satellite orbiting around the Earth. c) determine the distance of the geosynchronous satellite orbiting around the Earth. [G=6.67x10^-11 N m^2/kg^2] Me=5.98 x 10^24 kg