1, write a line by line explanation to the program. (35%) 2. Explain what the program does. (35%) 3, what will be displayed on the screen? (30%) .model small stack 100h 20040 6#32: Space| 64 40 100 1954: e i 96 60 140 oal 6#33: ! | 65 41 101 6f65; A | 97 61 141 G#97; 042 6#34. " | 66 42 102 6#66; B | 98 62 142 498, cF35; # | 67 43 103 '#67; C | 99 63 143 99 386 data ffh db 3ah sc db 0 36 24 044 36:? | 68 44 104458 ; D 1100 64 144 GE100 code main proc movax, @data up data segment #37:69 45 10569: 101 65 145 l0 38: 70 46 106 &70: F 102 66 146 c#10 47 6#39; ' | 71 47 107 71; G 1103 67 147 GAD : set 38 26 046 40 28 050 440; ( | 72 48 110 if72: H 104 68 150 al mov ds, axx 41 29 051 6: 73 49 111 73: 1 105 69 151 41 42 2A 052 442," 74 4A 112?74; J 1106 6A 152 Gil 43 2B 053 64375 4B 113 #75: 44 2C 0540144: , 45 2D 055 6#45; 46 2E 056 646: mov ah, 1 int 21h 107 63 153 | 76 4C 114 GF76: L |108 6C 154 4) cmp al, ffh JNS LPI sub ffh, Ah cmp al, ffh 8 4E 116 478:110 6E 156 6f 47 2F 057 647:79 4F 117 679;0 111 6F 157 f 48 30 060 648:0 80 50 120 480; P 112 70 160 49 31 061 6149; 1 jz ?pl mov dl, al cmp dl, 13 jz short skip push dx inc sc jmp 1pl | 81 51 121 481:0 |113 il 161 50 32 062 6#50; 2 | 82 52 122 82; R 1114 72 162 51 33 063 6#51:3 | 83 53 123 483; s 1115 ?3 163 G 52 34 064 6#52: 4 | 84 54 124?84. T 1116 74 164 53 35 065 6#53: 5 | 85 55 125 485; U 1117 75 165 54 36 066 G54; 6 86 56 126 4f86; 118 76 166 55 37 067 6#55; 7 | 87 57 127?87: u 1119 77 167 56 38 070 56; 8 88 58 130 6488: X 120 78 170 57 39 071 $57:9 89 59 131 89; 121 79 171 58 3A 072 6158; : | 90 5A 132 Z 1122 7A 172 59 3B 073 459: ; . | 91 5B 133 6#91; [ |123 7B 173 60 3C 074 460: 63 3F 077 6#63; ? | 94 SE 136 Gf94: A 1126 7E 176 | 95 SF 137 6f95:-1127 7F 177 pop dx mov ah, 6 int 21h dec sC jnz skip mov ax, 4c00h int 21h main endp end main