$1-$ Write and debug the code given below.

LDR R$2,=0001E8480$;

LDR RO$,=0$xFFEEDDC;

STR R$0,[$R$2]$;

As you finished debugging last instruction, open the "Memory" window in KEIL uVision IDE by

clicking on tab "Memory $1"$ as shown in Figure $1$ below. Type the memory address stored in

R$2$ in the "Address" bar of "Memory" window. Can you observe the data in R$0$ at address

Ox$001$E$8480?$ If not why?

Figure $1$: Screenshot of KEIL uVision IDE with "Memory" window at the bottom right corner.

$2-$ Modify the code given in question $1)$ such that the address stored in R$2$ becomes

$0$x$20000000.$ Save, build and debug the code again. As you finished debugging last

instruction, open the "Memory" window in KEIL uVision IDE by clicking on tab "Memory $1"$ as

shown in Figure $1.$ Type the memory address stored in R$2$ in the "Address" bar of "Memory"

window. Can you observe the data stored in R$0$ now at address $020000000?$ If yes, explain

why data can be stored in memory now but not in question $1?$ Content of which addresses

have changed in memory? Can you show that ARM processor use little endian format?

$3-$ Add the instructions given below to the code written in question $2.$ Save, build and debug the

code. As you finished debugging last instruction, check the content of register R$1.$ Is this the

result you expected? Explain your answer.

LDR R $2,=020000001$;

LDR R$1,[$R$2]$;

NOP

$4-$ Add the instructions given below to the code written in question $3.$ Save, build and debug the

code. As you finished debugging last instruction, open the "Memory" window in KEIL uVision

IDE by clicking on tab "Memory $1"$ as shown in Figure $1.$ Type the memory address stored in

register SP $($Stack Pointer$)$ in the "Address" bar of "Memory" window. Can you observe the

data stored in Stack? Write each data byte and the corresponding the address of each byte

stored in Stack. How does the value in register R$1$ is stored in Stack using little endian

format?

PUSH$[RO)$;

NOP;