Question: 10) 8 Marks, 4 for each part] Let an = 3n2+8 3n242. Then lim an = 1. We also have that 3n2 + 8 6

10) 8 Marks, 4 for each part] Let an = 3n2+8 3n242. Then lim an = 1. We also have that 3n2 + 8 6 -1= 3n2 + 2 (*) 3n2 + 2 a Use (*) above to show that if n > 100, then 3n2 + 8 3n2 + 2 -1/ N, then 3n2 + 8 3n2 + 2 -1

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