Question: 10. For operator D = dz 2x2 and equation D f(x) = 1 f(x) with boundary conditions f (0) = 0, f (It) = 0.

10. For operator D = dz 2x2 and equation D f(x)

10. For operator D = dz 2x2 and equation D f(x) = 1 f(x) with boundary conditions f (0) = 0, f (It) = 0. (a) Is f (x) = ex a solution to the above equation? Why or why not? If yes, what is the value of 1? (b) Is f(x) = -3Sin(4x) a solution to the above equation? Why or why not? If yes, what is the value of 1

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